Question

# Parallel side glass slab of thickness 8 cm is made of a material of refractive index √3. When light is incident on one of the parallel faces at an angle of 60∘ with the normal to the surface and emerges from other parallel face, find the lateral displacement of the emergent ray.

A
43 cm
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B
3 cm
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C
83 cm
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D
83 cm
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Solution

## The correct option is C 8√3 cm Given that, thickness (t)=8 cm , μ=√3 , i=60∘ From Snell's law, sinisinr=μ Substituting the given data we get, sin60∘sinr=√3⇒ sinr=sin60∘√3 ⇒sinr=√32√3=12 ⇒ r=30∘ For lateral displacement, δ=tsin(i−r)cosr Substituting the given data we get, δ=8×sin(60∘−30∘)cos30∘=8sin30∘cos30∘ ⇒ δ=8×12√32=8√3 cm Hence, option (c) is the correct answer. Why this question? This question helps student in application part of the formula of the lateral displacement due to a glass slab.

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