Partial $P$ of $H_{2}$ in $H_{2} O$ at $25^{o} C$ is 1 bar, constant for $H_{2}$ in $H_{2} O$ at $25^{o} C$ is $71.18$ bar. solublity of $H_{2}$ in $H_{2} O$ will be ?

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Solution

According to Henry law-
$P_{g} a s = K_{h} \times X_{a}$
$X_{a} = \frac{P_{g a s}}{K_{h}} = \frac{1}{71.18} = .014$

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Partial P of H2 in H2O at 25oC is 1 bar, constant for H2 in H2O at 25oC is 71.18 bar. solublity of H2 in H2O will be ?

According to Henry law-Pgas=Kh×XaXa=PgasKh=171.18=.014

Partial $P$ of $H_{2}$ in $H_{2} O$ at $25^{o} C$ is 1 bar, constant for $H_{2}$ in $H_{2} O$ at $25^{o} C$ is $71.18$ bar. solublity of $H_{2}$ in $H_{2} O$ will be ?

According to Henry law-
$P_{g} a s = K_{h} \times X_{a}$
$X_{a} = \frac{P_{g a s}}{K_{h}} = \frac{1}{71.18} = .014$