Partial pressure of water in air at a particular day is 8 torr at 14- C - Calculate the percentage relative humidityGiven- Vapour pressure of water at 14- C is 12 torr

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Standard XII

Chemistry

Mole Fraction

Partial press...

Question

Partial pressure of water in air at a particular day is $8 t o r r$ at $14^{\circ} C$ , Calculate the percentage relative humidity
Given: Vapour pressure of water at $14^{\circ} C$ is $12 t o r r$

66.67 %

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150 %

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112 %

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75 %

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Solution

The correct option is A $66.67 %$
Percentage Relative humidity ( $R . H$ ) is defined as :
$R.H = \frac{Partial pressure of water vapour}{Vapour pressure of water at the same temperature} \times 100 %$
$R.H = \frac{8 t o r r}{12 t o r r} \times 100 R.H = 66.67 %$

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Partial pressure of water in air at a particular day is 8 torr at 14∘C , Calculate the percentage relative humidity Given: Vapour pressure of water at 14∘C is 12 torr

The correct option is A 66.67%Percentage Relative humidity (R.H) is defined as : R.H=Partial pressure of water vapour Vapour pressure of water at the same temperature ×100% R.H=8 torr12 torr×100R.H=66.67%

Partial pressure of water in air at a particular day is $8 t o r r$ at $14^{\circ} C$ , Calculate the percentage relative humidity
Given: Vapour pressure of water at $14^{\circ} C$ is $12 t o r r$

The correct option is A $66.67 %$
Percentage Relative humidity ( $R . H$ ) is defined as :
$R.H = \frac{Partial pressure of water vapour}{Vapour pressure of water at the same temperature} \times 100 %$
$R.H = \frac{8 t o r r}{12 t o r r} \times 100 R.H = 66.67 %$