Partial reduction of alkynes under $H_{2} / P d$ conditions gives:

Anti products

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Syn products

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Both anti and syn in equal quantities

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It is determined by whether the alkyne is terminal or not

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Solution

The correct option is A Syn products
Partial reduction of alkynes under H2/Pd condition gives syn products.
Syn products are also obtained when Lindlar catalyst is used.
However, when Na/ ammonia is used, trans products are obtained.

Option B is correct.

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