Particle A of mass m1 moving with velocity (√3^i+^j) ms−1 collides with another partice B of mass m2 which is at rest initially. Let →V1 and →V2 be the velocities of particles A and B after collision respectively. If m1=2m2 and after collision →V1=(^i+√3^j)ms−1, the angle between →V1 and →V2 is :
→v1 will make an agle θ with x− axis.
Similarly, →v2=2(√3−1)^i−2(√3−1)^j will make angle ϕ with x− axis.
So, the angle between →v1 and →v2 will be 60∘+45∘=105∘.