Particle is moving in a straight path with an acceleration a=btn, where b is a positive constant (n≠−1). The relation between the velocity and the position vector of the particle at time t = 1s [Assuming particle is in rest at origin at t=0]
Given that,
a=btn
dvdt=btn
dv=btndt
v=btn+1n+1........(1)
drdt=btn+1n+1
dr=bn+1∫tn+1dt
r=bn+1tn+2n+2
r=Vtn+2(from1)
att=1s
V=(n+2)r