Question

Particle moving with a velocity ${\frac{1}{10}}^{th}$ of light will cross a nucleus in about

• A. ${10}^{-8}s$
• B. ${10}^{-12}s$
• C. ${10}^{-47}s$
• D. ${10}^{-21}s$

Answer 1

The correct option is D ${10}^{-21}s$

Velocity of particle $=\frac{C}{10}$$=3\times {10}^{7}m/s$

Assuming radius of nuclues $={10}^{-14}m$

The time $=\frac{2\times {10}^{-14}}{3\times {10}^7}$$=0.667\times {10}^{-21}s$