Particle of mass 0.3 kg is subjected to a force F = –kx with k = 15 N/m. What will be its initial acceleration if it is released from a point 20 cm away from the origin:
10 m/s2
mass = 0.3 kg, x = 20 cm
K = 15 N/m
F = -kx = ma
−15×20100=0.3aa=−10m/s2
-ve sign indicates acceleration is towards mean position