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Question

Particle P shown in figure is moving in a circle of radius R=10 cm with linear speed v=2 m/s. Find the angular speed of particle about point O

A
10 rad/s
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B
20 rad/s
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C
30 rad/s
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D
40 rad/s
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Solution

The correct option is A 10 rad/s


Angular velocity of particle wrt centre C
ωc=vR=vR=20.1
ωc=20 rad/s





from above figure at any position P, if the particle subtends an angle θ at O, corresponding angle at C is 2θ

So, Angular velocity of particle wrt centre C
ωc=ddt(2θ)=2dθdt

Angular velocity of P about O is
ω0=dθdt=ωc2
ω0=10 rad/s

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