Question

Particles's position as a function of time is given by $x=-t^2+4t+4$. The maximum value of position co-ordinate of particle is:

Answer 1

Given,

$x=-t^2+4t+4$

So,

For the maximum value of a position coordinate of particle is

$\frac{ds}{dt}=0$

$-2t+4=0$

$t=2s$

Thus the maximum value of the position coordinate of the particle is:

$-(2{)}^2+4(2)+4$

$=8units$