Question

Parveen wanted to make a temporary shelter for her car, by making a box-like structure with tarpaulin that covers all the four sides and the top of the car (with the front face as a flap which can be rolled up). Assuming that the stitching margins are very small, and therefore negligible, how much tarpaulin would be required to make the shelter of height $2.5m$, with base dimensions $4m\times 3m$ ?

Answer 1

Solution :-

Dimension of the non-like structure = $4m\times 3m\times 2.5m$

Tarpaulin only required for all the

for sides and top.

Thus Tarpaulin required = $2(l+b)\times h+lb$

$=\left[2\right(4+3)\times 2.5+4\times 3]m^2$

$=[35+12]m^2$

$=47m^2$