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Question

Parveen wanted to make a temporary shelter for her car, by making box-like structure with tarpoulin that covers all the four sides and the top of the car (With the front face as a flap which can be rolled up). Assuming that the stitching margins are very small, and therefore negligible, how much tarpaulin would be required to make the shelter of height 2.5m, with base dimensions 4m×3m?

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Solution

Given that l=4m;b=3m;h=2.5m

Required Area =lb+2bh+2lh

Required Area =(4×3)+2(3×2.5)+2(4×2.5)

Required Area =(12+15+20)m2

Required Area =47m2

991702_1086109_ans_a8a0a10af7c34847ab117137ab565a67.png

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