Question

Parween wanted to make a temporary shelter for her car, by making a box-like structure with tarpaulin that covers all the four sides and the top of the car(with the front face as a flap which can be rolled up)
Assuming that the stitching margins are very small, and therefore negligible, how much tarpaulin would be required to make the shelter of height $2.5m$, with base dimensions $4m\times 3m$?

• A. $47m^2$
• B. $57m^2$
• C. $41m^2$
• D. $37m^2$

Answer 1

Answer: (A)

$47m^2$

For shelter
length $l=4m$, breadth $b=3m$, height $h=2.5m$
$\therefore$ Total surface area of the shelter
$=2(l+b)h+lb$
$=2(4+3)\left(2.5\right)+\left(4\right)\left(5\right)$
$=2\left(7\right)\left(2.5\right)+12=47m^2$
Hence $47m^2$ of tarpaulin will be required.