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Question

Passage:
If n is the positive integer and if (1+4x+4x2)n=2nr=0arxr, where ai r are
(i=0,1,2,3,...2n) real numbers. On the basis of above information answer the following questions. The value of 2nr=0a2r is

A
9n1
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B
9n+1
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C
9n2
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D
9n+2
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Solution

The correct option is B 9n+1
(1+4x+2x2)n
(1+2x)2n ------------(i)
=2n0arxr
Substituting x=1 in equation (i), we get
32n ------------(a)
Substituting x=1 in equation (i). we get
(1)2n --------------(b)
Adding a and b, we get
2n0a2r=32n+1
=9n+1

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