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Byju's Answer

Standard XII

Chemistry

Introduction

Passage of on...

Question

Passage of one ampere current through 0.1 M Ni(NO₃)₂ solution using Ni electrodes bring in the concerntration of solution to _________in 60 seconds:

0.1M

0.05M

0.2M

0.025M

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Solution

Step 1:
Current, I = 1A

Time, t = 1 × 60 = 60 s (1 min = 60 second)

Charge = I × t

= 1 × 60 = 60 Coulombs

Step 2:

Charge on Ni,

No₃ has –1 charge always so that

Ni +2(NO₃) =0

Ni + 2(–1) = 0

Ni = +2

Charge required to deposited 1 mol of Ni = nF

= 2 × 96487 Coulombs

= 192974 Coulombs
Step 3:

1 mol of Ni = 58.7 g (use periodic table to get this value)

192974 Coulombs will generate = 58.7 g of Ni

60 Coulombs will generate = $\frac{58.7 g \times 60 C}{192974 C}$

= 0.00031 g

Hence, 0.0031 g of nickel will be deposited at the cathode.

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Passage of one ampere current through 0.1 M Ni(NO3)2 solution using Ni electrodes bring in the concerntration of solution to _________in 60 seconds: 0.1M 0.05M 0.2M 0.025M

Passage of one ampere current through 0.1 M Ni(NO₃)₂ solution using Ni electrodes bring in the concerntration of solution to _________in 60 seconds:

0.1M

0.05M

0.2M

0.025M