Pavan built a conical flask which required 550 $m^{2}$ of canvas. If the radius of flask is 7m, then how much water he can fill into the flask(in litres).

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Solution

Since, the area of canvas= 550 $m^{2}$ = $π$ rl

$\Rightarrow$ l = 25 m

$\Rightarrow$ h = $(l^{2} - r^{2})^{\frac{1}{2}}$

Volume of conical flask = $\frac{1}{3}$ $π$ $r^{2}$ h = 1232 $m^{3}$

We know that 1 $m^{3}$ = 1000 l

So, volume in litres = 1232000 l

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Pavan built a conical flask using 550 $m^{2}$ of aluminium sheet. If the radius of the flask is 7 m, then how much water can be filled in the flask(in litres)? [The bottom of the flask is of another material.]

Pavan built a conical flask using 550 $m^{2}$ of aluminium sheet. If the radius of the flask is 7m, then how much water can he fill into the flask?

Pavan built a conical flask using $550 m^{2}$ of aluminium sheet. If the radius of the flask is $7 m,$ then how much water can he fill into the flask (in litres)?
(The bottom of flask was made out of some other material.)

Q. A conical flask is full of water. The flask has base-radius

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and height

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. The water is poured into a cylindrical flask of base-radius

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. Find the height of water in the cylindrical flask.

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Pavan built a conical flask which required 550m2 of canvas. If the radius of flask is 7m, then how much water he can fill into the flask(in litres).

Since, the area of canvas= 550 m2 = πrl ⇒ l = 25 m ⇒ h = (l2−r2)12 Volume of conical flask = 13 πr2 h = 1232m3 We know that 1m3 = 1000 l So, volume in litres = 1232000 l

Pavan built a conical flask which required 550 $m^{2}$ of canvas. If the radius of flask is 7m, then how much water he can fill into the flask(in litres).

Since, the area of canvas= 550 $m^{2}$ = $π$ rl

$\Rightarrow$ l = 25 m

$\Rightarrow$ h = $(l^{2} - r^{2})^{\frac{1}{2}}$

Volume of conical flask = $\frac{1}{3}$ $π$ $r^{2}$ h = 1232 $m^{3}$

We know that 1 $m^{3}$ = 1000 l

So, volume in litres = 1232000 l