$P b_{3} O_{4}$ on reaction with $H N O_{3}$ forms $P b (N O_{3})_{2}$ and $P b O_{2}$ .

True

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False

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Solution

The correct option is A True
$P b_{3} O_{4} o r (2 P b O . P b O_{2})$
$P b_{3} O_{4} + H N O_{3} \to 2 P b (N O_{3})_{2} + P b O_{2} + 2 H_{2} O$

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Similar questions

M n O + P b O_{2} + H N O_{3} \to H M n O_{4} + P b (N O_{3})_{2} + H_{2} O

P b_{3} O_{4}

H N O_{3}

P b_{3} O_{4} + A \to 2 P b (N O_{3})_{2} + P b O_{2} + H_{2}

P b O_{2}

H N O_{3}

C O_{2}, S n O_{2}, P b O, P b O_{2}, P b_{3} O_{4}, A l_{2} O_{3}

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