Question

$Pb{F}_4,PbC{l}_4$ exists but $PbB{r}_4$ and $Pb{I}_4$ do not exist because of:

• A. Large size of $B{r}^{–}and{I}^{–}$
• B. Strong oxidising character of $P{b}^{4+}$
• C. Strong reducing character of $P{b}^{4+}$
• D. Low electronegativity of $B{r}^{–}and{I}^{–}$

Answer 1

The correct option is B Strong oxidising character of $P{b}^{4+}$

$P{b}^{4+}$ is a strong oxidising agent, as it has tendency to change to $P{b}^{2+}$, So it oxidises and $B{r}^{-}and{I}^{–}toB{r}_{2}and{I}_2$ respectively.