PbO $_{2}$ + 4HCl $\to$ PbCl $_{2}$ + 2H $_{2}$ O + Cl $_{2}$

In the above equation, the substance undergoing oxidation is _____.

lead dioxide

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hydrochloric acid

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chlorine gas

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lead chloride

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Solution

The correct option is D hydrochloric acid
As we all know that, oxidation is defined as the loss of electrons or increase in oxidation state whereas reduction is defined as the gain of electrons or decrease in oxidation state.
Now considering the oxidation state of chlorine in $H C l$ is -1. While the oxidation state of chlorine in $C l_{2}$ is 0. So the oxidation state of chlorine incresaes. So $H C l$ is undergoing through oxidation. Correct option is B

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Similar questions

M n O_{2} + 4 H C l \to M n {C l}_{2} + 2 H_{2} O + {C l}_{2}

In the above equation, name the compound which is oxidized and the compound which is reduced?

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and

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Q. In spectrochemical series, chlorine is above water i.e.,

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. This is due to:

calculate the mass of $M n O_{2}$ needed to produce 1.78 litres of chlorine gas at STP according to the equation
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[H = 1, Cl = 35.5, Mn = 54.9]

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PbO2 + 4HCl → PbCl2 + 2H2O + Cl2In the above equation, the substance undergoing oxidation is _____.

PbO $_{2}$ + 4HCl $\to$ PbCl $_{2}$ + 2H $_{2}$ O + Cl $_{2}$

In the above equation, the substance undergoing oxidation is _____.