${P B r}_{5}$ in solid state exists as ${[{P B r}_{4}]}^{+} {B r}^{-}$ . The expected shape of ${P B r}_{4}^{+}$ is
(1) Tetrahedral (2) Trigonal bipyramidal
(3) Square planar (4) Octahedral

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Solution

The correct answer is A
Tetrahedral because Br atoms are large and six atoms of Br cannot easily accommodated around smaller P atoms.

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