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Question

PbS + H2O2 =>PbSO4 + H2O
Balance completely by oxidation number method

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Solution

The oxidation number of Pb does not change in both sidesThe oxidation number of S in LHS = -2The oxidation number of S in RHS +2+x+4(-2)=0 x=+6Thus in the oxidation number change in S is 8. The oxidation number of oxygen in LHS = -1The oxidation number of oxygen in RHS = -2Thus in the oxidation number change in O is 1.PbS + H2O2 PbSO4 + H2O 8 2(1)Cross multiply,PbS + H2O2 PbSO4 + H2O 8 2(1)2PbS +8 H2O2 PbSO4 + H2O Thus balance the Lead and hydrogen in RHS2 PbS +8 H2O2 2 PbSO4 + 8 H2OPbS +4 H2O2 PbSO4 + 4 H2O

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