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Chemical Properties of Boron Family

PbS + H2O2 = ...

Question

PbS + H₂O₂ =>PbSO₄+ H₂O
Balance completely by oxidation number method

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Solution

$T h e o x i d a t i o n n u m b e r o f P b d o e s n o t c h a n g e i n b o t h s i d e s T h e o x i d a t i o n n u m b e r o f S i n L H S = - 2 T h e o x i d a t i o n n u m b e r o f S i n R H S + 2 + x + 4 (- 2) = 0 x = + 6 T h u s i n t h e o x i d a t i o n n u m b e r c h a n g e i n S i s 8 . T h e o x i d a t i o n n u m b e r o f o x y g e n i n L H S = - 1 T h e o x i d a t i o n n u m b e r o f o x y g e n i n R H S = - 2 T h u s i n t h e o x i d a t i o n n u m b e r c h a n g e i n O i s 1 . P b S + H_{2} O_{2} \to P b S O_{4} + H_{2} O 8 2 (1) C r o s s m u l t i p l y, P b S + H_{2} O_{2} \to P b S O_{4} + H_{2} O 8 2 (1) 2 P b S + 8 H_{2} O_{2} \to P b S O_{4} + H_{2} O T h u s b a l a n c e t h e L e a d a n d h y d r o g e n i n R H S 2 P b S + 8 H_{2} O_{2} \to 2 P b S O_{4} + 8 H_{2} O P b S + 4 H_{2} O_{2} \to P b S O_{4} + 4 H_{2} O$

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Q. Balance the following equation by oxidation number method.

P b S + H_{2} O_{2} \to P b S O_{4} + H_{2} O

Q. Balance the following equation :

P b S + H_{2} O_{2} \to P b S O_{4} + H_{2} O

Q. Balance the following equation by oxidation number method.

P b C r O_{4} + H_{2} S O_{4} + F e S O_{4} \to F e_{2} (S O_{4})_{3} + P b S O_{4} + C r_{2} (S O_{4})_{3} + H_{2} O

Q. Balance the following equations by oxidation number method.

H_{2} O_{2} + C l O_{2} + O H^{-} \to C l^{-} + O_{2} + H_{2} O

Q. Balance the following equation :

P b S + H_{2} O_{2} \to P b S O_{4} + H_{2} O

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