The correct option is C √(2) : 1 In the given figure : PCB is a right angled isosceles triangle nbsp;with right angle at C. BC = PC = 4 cm nbsp; PB = √(4^2 ...

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Finding Ratio of Sides in Triangle When Angles Are Given

Question

PCB is a right angled triangle. Find AB : PC, given BC = 4 cm.

1 : $\sqrt{2}$

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$2 \sqrt{2}$ : 1

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$\sqrt{2}$ : 2

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$\sqrt{2}$ : 1

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Solution

The correct option is D
$\sqrt{2}$ : 1

In the given figure :

PCB is a right-angled isosceles triangle with right angle at C.

BC = PC = 4 cm

PB = $\sqrt{4^{2} + 4^{2}}$

= $\sqrt{32}$

= $4 \sqrt{2}$ cm

PB = AB , since they are radii of the same circle.

$∴$ Ratio AB : PC = $4 \sqrt{2}$ : 4 = $\sqrt{2}$ : 1

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PCB is a right angled triangle. Find AB : PC, given BC = 4 cm.

The correct option is D √2 : 1 In the given figure : PCB is a right-angled isosceles triangle with right angle at C. BC = PC = 4 cm PB = √42+42 = √32 = 4√2 cm PB = AB , since they are radii of the same circle. ∴ Ratio AB : PC = 4√2 : 4 = √2 : 1