wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

PCl5 dissociates as PCl5(g)PCl3(g)+Cl2(g). If PCl5 is 10% dissociated at 1 atm, then the percentage of dissociation at 4 atm is:

A
2.5%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
4%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
5%
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
10%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 5%
PCl5(g)PCl3(g)+Cl2(g)
P1
P1(1α)P1αP1α
0.9P10.1P10.1P1
Now,
KP=PPCl3×PCl2PPCl5=(0.1P1)20.9P1=P190
Again,
1.1P1=1atm -- Total pressure
P1=11.1
So, KP=199
For new condition,
PCl5(g)PCl3(g)+Cl2(g)
P2
P2(1α)P2αP2α
P2(1+α)=4 -- Total pressure
KP=P2α21α=199
Note: 1α21 since α2<<1
α2=1396α=0.05

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Le Chateliers Principle
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon