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Byju's Answer
Standard XII
Chemistry
Le Chatelier's Principle for Del N Equals to 0
PCl5 dissocia...
Question
P
C
l
5
dissociates as
P
C
l
5
(
g
)
⇌
P
C
l
3
(
g
)
+
C
l
2
(
g
)
. If
P
C
l
5
is 10% dissociated at 1 atm, then the percentage of dissociation at 4 atm is:
A
2.5%
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B
4%
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C
5%
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D
10%
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Solution
The correct option is
C
5%
P
C
l
5
(
g
)
⇌
P
C
l
3
(
g
)
+
C
l
2
(
g
)
P
1
P
1
(
1
−
α
)
P
1
α
P
1
α
0.9
P
1
0.1
P
1
0.1
P
1
Now,
K
P
=
P
P
C
l
3
×
P
C
l
2
P
P
C
l
5
=
(
0.1
P
1
)
2
0.9
P
1
=
P
1
90
Again,
1.1
P
1
=
1
a
t
m
-- Total pressure
⇒
P
1
=
1
1.1
So,
K
P
=
1
99
For new condition,
P
C
l
5
(
g
)
⇌
P
C
l
3
(
g
)
+
C
l
2
(
g
)
P
2
P
2
(
1
−
α
)
P
2
α
P
2
α
⇒
P
2
(
1
+
α
)
=
4
-- Total pressure
K
P
=
P
2
α
2
1
−
α
=
1
99
Note:
1
−
α
2
≈
1
since
α
2
<
<
1
α
2
=
1
396
⇒
α
=
0.05
Suggest Corrections
0
Similar questions
Q.
At some temperature and under a pressure of 4 atm,
P
C
l
5
is 10% dissociated. Calculate the pressure at which
P
C
l
5
will be 20% dissociated, temperature remaining same.
Q.
At some temperature and under a pressure of 4 atm,
P
C
l
5
is 10% dissociated. Calculated the pressure at which
P
C
l
5
will be 20% dissociated temperature remaining same.
Q.
P
C
l
5
dissociates as
P
C
l
5
(
g
)
⇌
P
C
l
3
(
g
)
+
C
l
2
(
g
)
.
If total pressure at equilibrium of the reaction mixture is P and degree of dissociation of
P
C
l
5
is x, the partial pressure of
P
C
l
3
will be:
Q.
At some temperature and under a pressure of 4 atm,
P
C
l
5
is 10% dissociated. Calculated the pressure at which
P
C
l
5
will be 20% dissociated temperature remaining same.
Q.
The degree of dissociation of
P
C
l
5
at 1 atm pressure is 0.2. Calculate the pressure at which
P
C
l
5
is dissociated to 50%?
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