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Question

PCl5,PCl3andCl2 are at equilibrium at 500K in a closed container and their concentrations are 0.8×103molL1,1.2×103molL1 and 1.2×103molL1 respectively.
The value of Kc for the reaction:
PCl5(g)PCl3(g)+Cl2(g) will be:

A
1.8×103molL1
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B
1.8×103molL1
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C
1.8×103Lmol1
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D
0.55×104Lmol1
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Solution

The correct option is B 1.8×103molL1
The given reaction is :-

PCl5(g)PCl3(g)+Cl2(g)

KC=[PCl3][Cl2][PCl5]

=1.2×103×1.2×1030.8×103=1.8×103molL1

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