The correct option is A 5th period, Group 10
4d105s0 is the exceptional configuration of Pd becuase at higher atomic number energies are closer and hence 4d is filled over 5s. Its electronic configuration according to Aufbau principle should be [36Kr]4d8,5s2 thus its
period = 5th as n=5
Group = ns+(n−1)d electrons
= 2 + 8 = 10