Question

$Pd$ has exceptional valence shell electronic configuration of $4d^{10}5s^0$. It is a member of:

• A. $5^{th}$ Period , Group 10
• B. $4^{th}$ Period , Group 12
• C. $6^{th}$ Period , Group 10
• D. $5^{th}$ Period , Group 14

Answer 1

The correct option is A $5^{th}$ Period , Group 10

$4d^{10}5s^0$ is the exceptional configuration of Pd. Its electronic configuration should be ${[}_{36}Kr]4d^8,5s^2$ .
Thus, its
Period = 5th
Group = ns + ( n - 1 ) d electrons
= 2 + 8 = 10