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Standard XII
Chemistry
1900's Physics and Wave
PE is -27.2 e...
Question
PE is -27.2 eV in second or bit of He+ ion then calculate, double of total energy in first excited state of H atom
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Q.
Potential energy is
−
27.2
e
V
in second orbit of
H
e
+
then calculate, double of total energy in first excited state of hydrogen atom:-
Q.
Potential energy is -27.2 eV in the second orbit of
H
e
+
, then calculate double of total energy in the first excited state of hydrogen atom.
Q.
The ground state energy of hydrogen atom is
−
13.6
eV. The energy of second excited state
H
e
+
i
o
n
in eV is:
Q.
In a mixture of
H
−
H
e
+
gas, H atom and
H
e
+
ions are excited to their respective first excited states. Subsequently, H atoms transfer its excitation energy to
H
e
+
ions by collision.
If each hydrogen atom in the ground state is excited by absorbing photons of energy 8.4 eV, 12.09 eV, of energy, then assuming the Bohr model of an atom is applicable the number of spectral lines emitted is equal to:
Q.
If the ionisation energy for
H
atom is
13.6
e
V
, then calculate the energy in eV when the atom is excited from the ground state to the first excited state?
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