$P E = \frac{1}{4 π ϵ_{0}} \frac{Z e . (- e)}{r}$
In this expression should we take $(- e)$ value or $(e)$ value ?

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Solution

We should take (e) value as it is a positive number, on the other hand, the charge of electron is -e.

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Similar questions

Q. If

\bar{E}

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If E and F are events such that $P (E) = \frac{1}{4},$
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If E and F are events such that P(E) =, P(F) = and P(E and F) =, find:(i) P(E or F), (ii) P(not E and not F).

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PE = 14πϵ0Ze.(−e)rIn this expression should we take (−e) value or (e) value ?

We should take (e) value as it is a positive number, on the other hand, the charge of electron is -e.

$P E = \frac{1}{4 π ϵ_{0}} \frac{Z e . (- e)}{r}$
In this expression should we take $(- e)$ value or $(e)$ value ?