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Question
Pent-4-yn-2-ol has the structure:
Pent-4-yn-2-ol has the structure:
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Solution
The correct option is D
From the name pent-4-yn-2ol,we have
Word root=pent⇒5 carbon atoms
Primary suffix= yne (indicates a trible bond)
Secondary suffix=ol(the compounds has -OH as the primary functional group)
There are no other substituents.
Now we attempt to draw thw structure of tghe compound with the above information in mind.
1.C−C−C−C−C{ 5 carbon atoms}
2.C−C−C−C≡ C{ trible bond at C4}
3. C−C−C−C≡ C{ add the−OH group atC2}
(4) 1CH3−2C|HOH−3CH2−4C≡ 5CH { Completethe tetra−valency ofeach carbon with Hydrogen atoms}
Hence (a) is correct. But if we reverse structure with respect to the trible bond and -OH group we get (b)
5CH≡4C−3CH2−2C|HOH−1CH3
(a)=(b)=Pent−4−yn−2−ol}
From the name pent-4-yn-2ol,we have
Word root=pent⇒5 carbon atoms
Primary suffix= yne (indicates a trible bond)
Secondary suffix=ol(the compounds has -OH as the primary functional group)
There are no other substituents.
Now we attempt to draw thw structure of tghe compound with the above information in mind.
1.C−C−C−C−C{ 5 carbon atoms}
2.C−C−C−C≡ C{ trible bond at C4}
3. C−C−C−C≡ C{ add the−OH group atC2}
(4) 1CH3−2C|HOH−3CH2−4C≡ 5CH { Completethe tetra−valency ofeach carbon with Hydrogen atoms}
Hence (a) is correct. But if we reverse structure with respect to the trible bond and -OH group we get (b)
5CH≡4C−3CH2−2C|HOH−1CH3
(a)=(b)=Pent−4−yn−2−ol}
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