Percent by mass of a solute (molar mass = 28 g) in its aqueous solution is 28. Calculate the mole fraction (X) and molality (m) of the solute in the solution.
X = 0.2, m = 1259
Mol. of solute in 100 g solution =2828=1
Mol. of water in 100 g solution =100−2818=4
Mol. fraction of solute =11+4=0.2;
Molality =1×100072=1259