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Percentages

Percentage co...

Question

Percentage composition of carbon in the compound tetrahydrocarbinol is:

A

60.46%

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B

70.85%

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C

80.13%

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D

59.64%

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Solution

The correct option is C 80.13%
Molecular formula of tetrahydrocannabinol = $C_{21} H_{30} O_{2}$

Molor mass of tetra hydrocannabinol = $\frac{1}{0.00318}$ = 314.45 $g m M o l^{- 1}$

Percentage composition of C = $\frac{12 \times 21}{314.45} \times 100$

= 80.13 %

Hence. the correct option is $(C)$ .

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