Percentage composition of hydrogen in benzene ( $C_{6} H_{6}$ ) is .

8 %

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7.7 %

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50 %

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5 %

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Solution

The correct option is B $7.7 %$
Molecular mass of benzene is $= (12 \times 6) + (6 \times 1) = 78 u$
Mass percentage of an element $= \frac{Mass of an element}{Mass of compound} \times 100 = \frac{6}{78}$ $\times 100$ $= 7.7 %$

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