Percentage composition of hydrogen in benzene ( $C_{6} H_{6}$ ) is :

8 %

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7.7 %

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50 %

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5 %

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Solution

The correct option is B $7.7 %$
Molecular mass of benzene is $= (12 \times 6) + (6 \times 1) = 78 u$

Mass percentage of an element= $\frac{Mass of an element}{Mass of compound} \times 100$ = $\frac{6}{78}$ $\times 100$ $= 7.7 %$

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Similar questions

Carbon combines with hydrogen to form three hydrocarbons A, B, and C. The percentage of hydrogen in A, B, and C is 25, 14.3, and 7.7 respectively.

Percentage composition of hydrogen in benzene ( $C_{6} H_{6}$ ) is :

C_{6} H_{6}

C_{6} H_{6}

C_{6} H_{6}

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