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Question

Percentage of calcium in calcium carbonate is ________.


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Solution

Step 1:Molecular mass of calcium carbonate (CaCO3 ) = 40 + 12 + 16 ✕ 3 = 100 u

Step 2: Atomic mass of calcium = 40 u

Mass of calcium in 1 mole of CaCO3 = 40 grams

Step 3:Mass percentage of an element = mass of an element/mass of compound ✕ 100

Percentage of calcium = 40/100 ✕ 100 = 40%

Final Answer:
The percentage of calcium in calcium carbonate is 40%.



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