Question

Percentage of $p-$orbital character is maximum is the central atom of which of the following?

• A. $C{H}_4$
• B. $Xe{F}_2$
• C. $B{F}_3$
• D. $BeC{l}_2$

Answer 1

Answer: (A)

$C{H}_4$

$C{H}_4⟶s{p}^3$ hybridized, % $p$ character= $\frac{3}{4}\times 100=75$ %

$Xe{F}_2⟶s{p}^{3}d$ hybridized, % $p$ character=$60$ %

$B{F}_3⟶s{p}^2$ hybridized, % $p$ character= $\frac{2}{3}\times 100=66.6$ %

$BeC{l}_2⟶sp$ hybridized, % $p$ character= $50$ %

The maximum $p$-orbital character is $C$ in $C{H}_4$ .