wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Percentage of recombination between A and B is 9%, A and C 17% and B and C is 26%. The arrangement of genes would be

A
A-B-C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
A-C-B
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
B-C-A
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
B-A-C
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is B B-A-C
1 map unit or centimorgan is equivalent to 1% recombination between the two genes. The frequency of recombination can be used to depict the arrangement of the genes.
Recombination frequency between three genes are
A-B=99%
A -C=17% and
B -C=26%
By manipulating the three possibilities of their arrangements A-B C, A -C-B and B- A-C, it was found that the three genes must be arranged in the order B -A-C with the distance between B -A being 9 cM and A-C being 17 cM and the distance between B-C being 26 cM.

So, the correct answer is 'B-A-C'.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
BIOLOGY
Watch in App
Join BYJU'S Learning Program
CrossIcon