Question

Percentage of Se in peroxidase anhydrous enzyme is $0.5\%$ by weight $(\mathrm{At}.\mathrm{wt}=78.4).$ What is the minimum molecular weight of peroxidase anhydrous enzyme?

Answer 1

Step 1: Given data:

We are given a peroxide anhydrous enzyme in which Se is present as = $0.5\%$ by weight
This means we can say that $0.5\mathrm{g}\mathrm{of}\mathrm{Se}$ is present in $100\mathrm{g}$ of the enzyme.

The atmoic weight of Se is given as = $78.4\mathrm{gm}$

Step 2: Calculation of molecular weight of peroxidase anhydrous enzyme:
$78.4\mathrm{g}\mathrm{of}\mathrm{Se}$ will be present in,

=${\displaystyle \frac{100}{0.5}}\times 78.4$

=$1.568\times {10}^4$gm of peroxidase anhydrous enzyme

Hence, the minimum molecular weight of peroxidase anhydrous enzyme is calculated as $1.568\times {10}^4$gm.