Question

Perform the following division:
$(3pqr-6p^2{q}^2{r}^2)÷3pq$

Answer 1

The dividion is carried out as follows :

$\frac{3pqr-6p^2{q}^2{r}^2}{3pq}$

$=\frac{3pqr}{3pq}-\frac{6p^2{q}^2{r}^2}{3pq}$

$=\frac{3\cdot p\cdot q\cdot r}{3\cdot p\cdot q}-\frac{2\cdot 3\cdot p\cdot p\cdot q\cdot r\cdot r}{3\cdot p\cdot q}$

Cancelling out the common factors in numerator and denominator,

$=r-2\cdot p\cdot q\cdot r\cdot r$

$=r-2pq{r}^2$