Question

Perimeter of a parallelogram is 150 cm. One of its sides is greater than the other side by 25 cm. Find the lengths of all sides.

Answer 1

Let PQRS be the parallelogram.
Let the length PQ be x.
Given other side is greater by 25cm.
PS = x+25
Since opposite sides of a parallelogram are equal,
PQ = SR
PS = QR
Given perimeter of PQRS = 150cm.
$PQ+QR+SR+PS=150$
$x+x+25+x+x+25=150$
$4x+50=150$
$4x=150-50$
$4x=100$
$x=\frac{100}{4}=25$
$PQ=SR=x=25\text{cm}$
$PS=QR=x+25=25+25=50\text{cm}$
Hence the lengths of the sides of the parallelogram are 25 cm , 50 cm , 25 cm and 50 cm.