Perimeter of a rectangle is 44 cm. If its length is 9 cm, then its breadth is

13 cm

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12 cm

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11 cm

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10 cm

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Solution

The correct option is A
13 cm

We know that if ' $l$ ' is the length of the rectangle and ' $b$ ' is its breadth, then its perimeter is given by

$P = l + b + l + b = (2 \times l) + (2 \times b)$

Given $P = 44 cm$ and $l = 9 cm$

Then,

$P = (2 \times l) + (2 \times b)$

$⟹ b = \frac{P - (2 \times l)}{2}$

i.e., $b = \frac{44 - (2 \times 9)}{2} = 13 cm$

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Perimeter of a rectangle is 44 cm. If its length is 9 cm, then its breadth is

The correct option is A 13 cm We know that if 'l' is the length of the rectangle and 'b' is its breadth, then its perimeter is given by P=l+b+l+b=(2×l)+(2×b) Given P=44 cm and l=9 cm Then, P=(2×l)+(2×b) ⟹b=P−(2×l)2 i.e., b=44−(2×9)2= 13cm