Question

Perimeter of $△ABC$ is 14cm, AB=4.5 cm and $\angle A={80}^o$. Construct $△ABC$.

Answer 1

1. Draw AB= 4.5 cm

2. Draw angle 80 deg at A and cut an arc of AD= 9.5 cm. (14- 4.5 = 9.5)

3. Join BD.

4. Draw perpendicular bisector of BD which meets AD at C.

5. Join BC

ABC is the required triangle.