Perimter of triangle ABC is 20 cm and AC = BC= 7 cm. CP = ____
4 cm
Given, AE = BC = 7
and AC + BC + AB = 20
AB = 20 - 7 - 7 = 16 cm
PC = x cm
AP = 7 - x (as AC = 7 cm)
AQ = 7 - x [Tangents from an external point are equal in length]
AB = 2(7 - x) [ABC is an isosceles triangle]
2(7 - x) = 3
x = 4 cm
PC = 4 cm