Permanent hardness is due to presence of soluble salts of Mg and Ca in the form of chlorides and sulphates in $H_{2} O$ . It can be removed by

Boiling

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Clark’s method

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Treatment with Na₂CO₃

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All of these

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Solution

The correct option is C
Treatment with Na₂CO₃

Permanent hardness of water is removed by

(a) $N a_{2} C O_{3}$

(b) Permuitit method

(c) Ion exchange process

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Similar questions

H_{2} O

A) Hardness of water	(1) Removed by simple boiling
B) Temporary hardness	(2) Carbonates, chlorides, and sulphates of $C a$ and $M g$
C) Calgon	(3) Bicarbonates, chlorides and sulphates of $C a$ and $M g$
D) Permutit	(4) $N a_{2} A l_{2} S i_{2} O_{8} . x H_{2} O$
	(5) $N a [N a_{4} (P O_{3})_{6}]$

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