Question

Permanganate ion acts as oxidising agent in acidic, neutral as well as alkaline medium. Consider the reactions of permanganate ion:

I. $I^{-}+Mn{O}_4^{-}\underset{\text{Medium}}{\overset{\text{Acidic}}{\to }}$

II. $I^{-}+Mn{O}_4^{-}\underset{\text{or faintly alkaline medium}}{\overset{\text{Neutral}}{\to }}$

The oxidation state of iodine in reactions I and II are respectively

• A. Zero in both reactions
• B. Zero in I and $+3$ in II
• C. $+3$ in I and zero in II
• D. Zero in I and $+5$ in II

Answer 1

The correct option is D Zero in I and $+5$ in II

$10I^{-}+2Mb{O}_4^{-}+16H^{+}\to 8H_2+5I_2$

$2Mn{O}_4^{-}+H_{2}O+I^{-}\to 2Mn{O}_2+2O{H}^{-}+I{O}_3^{-}$