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Question

Peroxide linkage is present in:

A
H2O2
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B
BaO2
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C
OF2
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D
H2S2O8
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Solution

The correct options are
A H2O2
B BaO2
D H2S2O8
In peroxide linkage, oxygen has -1 oxidation state so we calculate the oxidation of oxygen to know about the presence of peroxide linkage.

In H2O2, as oxidation state of hydrogen is +1 so the oxidation state of oxygen is -1. So it has peroxide linkage.

In BaO2, as oxidation state of barium is +2 so the oxidation state of oxygen is -1. So it has peroxide linkage.

In OF2, as oxidation state of fluorine is -1 as it is more electronegative than oxygen so the oxidation state of oxygen is +2. So it has no peroxide linkage.

In H2S2O8, the highest possible oxidation state of S is +6 and two oxygen must be attached to each other through peroxide linkage. So it has peroxide linkage.

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