Question

Peroxide linkage is present in:

• A. $H_2{O}_2$
• B. $Ba{O}_2$
• C. $O{F}_2$
• D. $H_2{S}_2{O}_8$

Answer 1

Answer: (A), (B), (D)

The correct options are
A $H_2{O}_2$
B $Ba{O}_2$
D $H_2{S}_2{O}_8$

In peroxide linkage, oxygen has -1 oxidation state so we calculate the oxidation of oxygen to know about the presence of peroxide linkage.

In $H_2{O}_2,$ as oxidation state of hydrogen is +1 so the oxidation state of oxygen is -1. So it has peroxide linkage.

In $Ba{O}_2,$ as oxidation state of barium is +2 so the oxidation state of oxygen is -1. So it has peroxide linkage.

In $O{F}_2,$ as oxidation state of fluorine is -1 as it is more electronegative than oxygen so the oxidation state of oxygen is +2. So it has no peroxide linkage.

In $H_2{S}_2{O}_8,$ the highest possible oxidation state of S is +6 and two oxygen must be attached to each other through peroxide linkage. So it has peroxide linkage.