$P H_{3} + O_{2} \to P_{2} O_{5} + H_{2} O$
Above equation is balanced and coefficients are the lowest whole number, find the coefficient for $H_{2} O$ ?

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Solution

The correct option is B 3
The unbalanced chemical equation is $P H_{3} + O_{2} \to P_{2} O_{5} + H_{2} O$
Balance $P$ atoms by adding 2 to $P H_{3}$ on LHS
$2 P H_{3} + O_{2} \to P_{2} O_{5} + H_{2} O$
Balance H atoms by adding 3 to $H_{2} O$ on RHS
$2 P H_{3} + O_{2} \to P_{2} O_{5} + 3 H_{2} O$
Balance O by adding 4 to $O_{2}$ on LHS
$2 P H_{3} + 4 O_{2} \to P_{2} O_{5} + 3 H_{2} O$
This is the balanced chemical equation.
The coefficient of water is 3.

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