$P h - C \equiv C - C H_{3} H g^{2 +} / H^{+} - ----- \to A$ . A is

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A a
a) $C_{6} H_{5} - C \equiv C - C H_{3} H g S O_{4} - --- \to H_{2} S O_{4} C_{6} H_{5} - O | | C - C H_{2} - C H_{3}$

Suggest Corrections

Similar questions

C H_{3} - O | | C - H (i); C H_{3} - O | | C - C H_{3} (i i); E t - O | | C - H (i i i)

C H_{3} - C H_{2} - C H_{2} - O | | C - H (i v); P h - O | | C - C H_{3} (v); P h - O | | C - P h (v i)

P h M g B r

P h - O | | C - P h

C H_{3} - O | | C - H

C H_{3} - O | | C - C H_{3}

C H_{3} - O | | C - C H_{3}

H - O | | C - C H_{3}

P h - O | | C - P h

Ph - C \equiv N H_{3} O^{+} - --------- \to Partial Hydrolysis (A) {Br}_{2} + KOH - ---- \to (B)

(A)

C H_{3} C H_{2} N H_{2}

(B)

C H_{3} C H_{2} C H_{2} C H_{3} | N H

(C)

H_{3} C - C H_{3} | N - C H_{3}

(D)

P h - C H_{3} | N - H

Join BYJU'S Learning Program