P hC - CH 3 Hg 2- H - A

The correct option is A PhC ≡ C CH_3 ...

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Halides of Group 16

P hC ≡ CH 3 H...

Question

$P h C \equiv C H_{3} H g^{2 +}, H^{+} - ----- \to A$

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Solution

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Similar questions

P h C O C H_{3} P h C O_{2} H ⟶ (A)

P h C {+ H}_{2}

C H_{2} = C H - C {+ H}_{2}

$P h C \equiv C - C H_{3} H_{3} O^{+} / H g^{+ 2} - ------- \to A$ . Then 'A' is

2 P h - C H O {O H}^{-} - ---------- \to P h - C H_{2} - O H + P h C O_{2}^{-}

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