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Byju's Answer
Standard XII
Chemistry
Ozonolysis
Ph-CH2-CH=Me|...
Question
P
h
−
C
H
2
−
C
H
=
C
|
M
e
−
P
h
(
i
)
O
3
−
−−−
→
(
i
i
)
H
2
O
U
+
V
U
+
V
N
a
H
S
O
3
→
Only U precipitates out.
V
R
e
d
P
/
B
r
2
−
−−−−−
→
H
2
O
W
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Solution
P
h
−
C
H
2
−
C
H
=
C
|
M
e
−
P
h
O
3
−
−
→
H
2
O
P
h
−
C
H
2
−
C
O
O
H
+
M
e
−
O
|
|
C
−
P
h
→
Reaction is oxidation ozonalysis
U
+
V
N
a
H
S
O
3
−
−−−−
→
U
precipitate out
Therefore , U is
M
e
−
O
|
|
C
−
P
h
as only ketons undergo
N
a
H
S
O
3
addition
P
h
−
C
H
2
−
C
O
O
H
R
e
d
P
/
B
r
2
−
−−−−−
→
H
2
O
P
h
−
B
r
|
C
|
H
−
C
O
O
H
This reaction is known as Hell-Volhard-Zelinsky-reaction [HVZ]
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e
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−
−−−−
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=
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